A circle with centre (3, 2) passes through the point (6, 3). What is the radius of the circle: (6, 3)
Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
Answer
Given points (3,2) and (6,3) (Using the distance formula)
r=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
(6−3)
2
+(3+2)
2
=
3
3
+1
2
=
10
b. (3,2) and (0,2) (Using the distance formula)
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
(0−3)
2
+(2+2)
2
=
9
=3
Here 3 is less than the radius, so the point is inside the circle.
(3,2) and (3,6) (Using the distance formula)
(3−3)
2
+(6−2)
2
=
0
2
+4
2
=
16
=4
Here 4 is greater than the radius, so the point be outside the circle.
(3,2) and (0,3) (Using the distance formula)
(0,−3)
2
+(3−2)
2
=
9+1
=
10
Here $$\sqrt{10} is equal the radius, so the point be on the circle.
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