a circle with centre at O and angle aob is equal to 90 degrees if the radius of the circle is 40 centimetres calculate the area of the shaded portion of the circle take Pi 3.14
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So since there's an angle of 90°
Then the required area enclosed will be a quarter of area of the circle.
Using this relation we get
![\frac{1}{4} \times \pi ({40)}^{2} \\ \\ \frac{1}{4} \times 3.14 \times {(40)}^{2} = 1256 {m}^{2} \frac{1}{4} \times \pi ({40)}^{2} \\ \\ \frac{1}{4} \times 3.14 \times {(40)}^{2} = 1256 {m}^{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B4%7D++%5Ctimes+%5Cpi+%28%7B40%29%7D%5E%7B2%7D++%5C%5C++%5C%5C++%5Cfrac%7B1%7D%7B4%7D++%5Ctimes+3.14+%5Ctimes++%7B%2840%29%7D%5E%7B2%7D++%3D+1256+%7Bm%7D%5E%7B2%7D+)
Then the required area enclosed will be a quarter of area of the circle.
Using this relation we get
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