Question

. A circle with centre O and radius 12.5 cm passes through points P,Q and R. Seg PQ is the diameter of the circle. If l(PR)=20 cm, then l(RQ)=______. *

•15m

•10cm

•30cm

•15cm​

Answer 1

Answer:

Option D: 15 cm

Step-by-step explanation:

Data:

Diameter= 12.5 x 2= 25 cm

PR= 20 cm

We need to apply Pythagoras Theorem i.e.

H^2=P^2 + B^2

H will be the diameter;

B will be (PR); and

P will be (RQ)

(25)^2=P^2 + (20)^2

P^2=225

P=15 cm