a circle with centre O is given in which a diameter AB bisects the chord CD at a point E such that CE = ED = 8cm and EB=4cm find the radius of the circle
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Let the radius of circle be x cm
OE=x-4
OC=x
CE=8cm
In triangle OCE
By pythagoras theorem
OC = CE +OE
OC =64+x^2-4x +16
x^2=64 +x^2-4x+16
4x=80
x=20
I hope a brainiest if you think it worthy
OE=x-4
OC=x
CE=8cm
In triangle OCE
By pythagoras theorem
OC = CE +OE
OC =64+x^2-4x +16
x^2=64 +x^2-4x+16
4x=80
x=20
I hope a brainiest if you think it worthy
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2
Answer:
in the given figure a circle with Centre with given in which a diameter ab bisects the Jod ACD at a point is such that AC is equal to 8 equal to 8 cm and equal to 4 cm find the radius of the circle.
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