A circle with centre O, OM perpendicular to AB, ON perpendicular to CD, OM = ON = 3.9 cm and AB = 8.6 cm. Find I(CD).
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Let the radius of a circle be x.
So, OC=OD=x
As, OB=OE+EB
x=OE+4
OE=x - 4
Hence OE is perpendicular to CD
In traingle OED
OE
2
+ED
2
= OD
2
(x - 4)
2
+8
2
=x
2
x
2
+16-8x+64 = x
2
-8x+80 = 0
8 x = 80
x = 10 cm
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