Question

A circle with centre O touches the side of triangle ABC at D,E,F and AB =AC.To prove :BE=EC​

Answer 1

Answer:AD=AF (tangents from   an external  point is equal)

Step-by-step explanation:SIMIlarly

BD=BE(tangents from  an external   point are equal)

and CF=CE(tangents from  an external   point are equal)

since AB=AC, AD+DB=AF+CF

(AD=AF therefore AD+DB=AD+CF

AD AD CANCEL OUT therefore DB=CF proof)

therefore  DB=CF.

simple explanation :  since DB=CF BE=CE

because BD=BE and CE=CF we can equate  that

BE= CE

hope you understood note you can read CE or  EC they are  the same .