a circle with centre P touches the semicircle at point Q and C having centre O if diameter AB=10,AC=6 then find the radius of the smaller circle
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Answer:
let OQ intersects smaller circle at M.
And OM be y.
In ∆OCP,<C =90°
So by Sulba Sutra,
OP²=PC²+OC²
=(y+x)²=x²+1
=(5-x)²=x²+1. ...( •.•OP=OQ-PQ)
=25-10x+x²=x²+1
=25 - 10x=1
=24=10x
=x=2.4
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