Question

A circle with diameter AB and center C is drawn and another radius CD is also drawn such that cD makes 60° A dice is thrown into the circle what is the probability that the dice will fall in the sector region of ACD​

Answer 1

Answer:

Correct option is

A

4

4−π

Area of the shaded region = Area of the square −4× Area of the sector of the circle

area of a circle =(2×2)−4×

4

1

(π)(1)

2

=4−π

Required probability=

Area of square

Area of shaded region

=

4

4−π

hope this is help you☺ friend