A circle with diameter AB and center C is drawn and another radius CD is also drawn such that CD makes 60° A dice is thrown into the circle what is the probability that the dice will fall in the sector region of ACD
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Answer:
Area of the shaded region = Area of the square −4× Area of the sector of the circle
area of a circle =(2×2)−4×
4
1
(π)(1)
2
=4−π
Required probability=
Area of square
Area of shaded region
=
4
4−π
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