Question

A circle with diameter of 30 cm has a cord of 24 cm, then the distance of the cord from the center is....
Step-By-Step

Answer 1

Answer:

Using theorem perpendicular from the center bisect the chord the chord is bisected at 90 degree. So the two parts of line is 12 cm each. Applying Pythagoras theorem, Therefore, the distance of the chord from the center is 9 cm.

Step-by-step explanation:

please mark me brilliant ❤️

Answer 2

$\LARGE\underline{\blue{\sf{Question:-}}}$

A circle with diameter of 30 cm has a cord of 24 cm, then the distance of the cord from the center is....

$\LARGE\underline{\blue{\sf{Answer:-}}}$

Using theorem perpendicular from the center bisect the chord the chord is bisected at 90 degree.

So the two parts of line is 12 cm each. Applying Pythagoras theorem, Therefore, the distance of the chord from the center is 9 cm.