Question

A circle with its center at O (6,5) has a
radius of 5 units.
Point P (2,y) lies on the circle. Also,
y < 4.
Find y.​

Answer 1

Answer:

Hello mate..

Step-by-step explanation:

Answer :-

True

Explanation :-

Point Q (6, 8) will lie outside the circle if its distance from the centre of circle is greater then the radius of the circle.

Distance between centre O(0, 0) and P(5, 0)

⇒ OP = √(5 - 0)² + (0 - 0)²

⇒ OP = √(5)² + (0)²

⇒ OP = 5

As, point P lies at the circle,

Therefore,

OP = Radius of the circle.

Distance between centre O(0, 0) and Q(6, 8)

⇒ OQ = √(6 - 0)² + (8 - 0)²

⇒ OQ = √(6)² + (8)²

⇒ OQ = √36 + 64

⇒ OQ = √100

⇒ OQ = 10

As OQ is greater OP, therefore , point Q(6, 8) lies outside of the circle

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Answer 2

Answer:

CHINAAAAAAAAAAAAAA

Step-by-step explanation: