A circle with radius 6 c.m and a chord of 9.6 c.m. if a point P is the tangent to circle touching point A and B, what is the length of PA?
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dist. of chord from centre=sqrt( 6^2-4.8^2)=3.6
let's assume centre as O
and OP bisects chord at C.
assume CP = x
AP ^2=X^2+4.8^2
(3.6+X)^2=AP^2+6^2
(3.6+X)^2=X^2+4.8^2+6^2
3.6^2+7.2X+X^2=X^2+59.04
7.2X=46.08
X=6.4
let's assume centre as O
and OP bisects chord at C.
assume CP = x
AP ^2=X^2+4.8^2
(3.6+X)^2=AP^2+6^2
(3.6+X)^2=X^2+4.8^2+6^2
3.6^2+7.2X+X^2=X^2+59.04
7.2X=46.08
X=6.4
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