A circle with radius 9 has a secotor with central angle 120 whats the area of the sector
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Answer:
27π
Step-by-step explanation:
120° is 1/3rd of the whole 360°.
so the area of the sector is 1/3rd the area of the circle.
Now area of the circle is πr^2=π(9)^2=81π.
so, the area of sector is 1/3(81π)=27π.
Hope it helps u!
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