Question

a circle x^2+y^2-2ax+2y=0 cuts x axis at A and circumscribes an equilateral triangle with ao as one of its sides. find value of a and vertices of triangle
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Answer 1

Step-by-step explanation:

x

2

+y

2

−3x−4y+2=0

x-axis will be cut when y=0

put y=0

x

2

−3x+2=0

(x−2)(x−1)=0

x=1,2

points (1,0),(2,0)