Math, asked by dhananjayb439, 10 months ago

A circuit consist of
two parallel circuit. having
a resistance 20ohm and 30ohm respectively connected in series with 15ohm.the current through 15 ohm resistor is 3amps,then find the current through 20ohm and 30ohm resiator respectively.

Answers

Answered by TheMoonlìghtPhoenix
34

Answer:

Step-by-step explanation:

ANSWER:

There are two types of Circuits:-

\boxed{\textbf{PARALLEL CIRCUITS}}

In this type the resistances are added by adding their reciprocals and at last we again reciprocal the sum to get required answer.

\boxed{\textsf{SERIES CIRCUITS}}

In this type resistances are simply added to get the equivalent resistance.

Let the total Resistance be R.

Calculating Parallel circuit first,

GIVEN:-

2 Resistances of 20 ohm and 30 ohm.

Let the Equivalent resistance be R'.

\frac{1}{R'} = \frac{1}{20} +\frac{1}{30}

Taking LCM,

\frac{1}{R'} =\frac{3+2}{60} \implies \frac{5}{60} \implies \frac{1}{12}

\boxed{\boxed{\textsf{R' = 12 ohms}}}

Now we will add R' with 15 Ohm as it is in Series:-

R = 12+15

\boxed{\boxed{\textbf{R = Total Resistance = 27 Ohms}}}

Now we need to find the voltage.

\huge{\textsf{V = IR}}

  • Where V is voltage
  • Where I is current
  • Where R is Resistance

So,

V = 3 * 27

\boxed{\boxed{\textsf{Voltage = 81 Volts}}}

Now we need to find Current through each resistors where voltage will be same .

Using same Formula for 20 ohm first,

81 = 20*I

I = 81/20

\boxed{\textbf{Current through 20 Ohm resistor = 4.05 Ampere}}

Using the same formula for 30 ohm now,

81 = 30*I

I = 81/30

\boxed{\textsf{Current through 30 Ohm resistor = 2.7 Amperes}}

Answered by CrEEpycAmp
37

QUESTION:

  • A circuit consists of two parallel circuit having resistance 20 ohm and 30 ohm.

  • It is connected in series with 15 ohms.

  • The current through 15 ohm resistance is 3 amps.

To Find:

  • Current through 20 ohm and 30 ohm resistance.

FORMULA USED:

  • In parallel, equivalent resistance is given by. ...

1/Req = 1/R1 + 1/R2

  • In series, the equivalent resistance is given by...

Req = R1 + R2

  • Also, V = I*R [ ohm's law]

SOLUTION:

Equivalent resistance in parallel will be..

1/Req = 1/20 + 1/30

1/Req = 5/60

Req = 12 ohms

Now, this us connected in series with 15 ohm resistor,

So, Req = 12+15 = 27 ohm

Now, Total 3 A current passes through 15 ohm connect.

So, V = 3*27 = 81 ohms...(1)

Therefore, current through 30 ohm resistance will be...

81/30 = 2.7 A

Current through 20 ohm resistance will be....

81/20 = 4.05 A.

So, the currents will be 4.05 A and 2.7 A .

{\huge{\mathbb{\purple{HOPE \ IT \ HELPS}}}}

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