Physics, asked by rajveershukla5420, 6 months ago

A circuit consisting of a battery of three cells of 2 V each, a 5Ω resistor, an 8 Ω resistor,
and a 12 Ω resistor, and a plug key, all connected in series. Putting in an ammeter to
measure the current through the resistors and a voltmeter to measure the potential
difference across the 12 Ω resistor. What would be the readings in the ammeter and the
voltmeter?

Answers

Answered by rayyanuddin027
1

Explanation:

use v=ir^2.....................

Answered by rv21060
1

Explanation:

Three cells of potential 2 V, each connected in series therefore the potential difference of the battery will be 2 V + 2 V + 2 V = 6V. The following circuit diagram shows three resistors of resistances 5 Ω, 8 Ω and 12 Ω respectively connected in series and a battery of potential 6 V and a plug key which is closed means the current is flowing in the circuit.

chapter12

schematic diagram of a circuit consisting of a battery of three cells

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