Question

a circuit consists of three resistors 3, 4 and 6 in parallel and fourth resistor in series. A battery of e.m.f. 12 V and internal resistance 6 is connected across the circuit. Find the total current in the circuit & terminal voltage in the battery?​

Answer 1

Answer:

R1=3ohm R2=4ohm,R3=6ohm

As the resistors are connected in parallel

1/Rtotal=1/3+1/4+1/6

1/Rtotal=(4+3+2)/12

1/Rtotal=9/12

Rtotal=12/9

Rtotal=4/3 ohm

Total current=Voltage /Rtotal

Itotal=2/(4/3)

Itotal=6/4

Itotal=3/2 Ampere

For resistance in the parallel ,voltage across each resistor is same and total current is sum of current through each resistor.

Current through R1=V/R1=2/3 Ampere

Current through R1=V/R2=2/4=1/2Ampere

Current through R1=V/R3=2/6=1/3Ampere

Total current is 3/2 Ampere