Question

A circuit consists of three resistors of 3Omega 4Omega and 6Omega in parallel and a fourth resistor of 4Omega in series.A battery of e.m.f.12V and internal resistance 6Omega is connected across the circuit.Find the total current in the circuit and terminal voltage across the battery.​

Answer 1

Answer:

Hey mate the answer is:-

Explanation:

(a) For Parallel connection,

R

p

1

=

R

1

1

+

R

2

1

+

R

3

1

R

p

1

=

2

1

+

4

1

+

5

1

R

p

1

=

20

10+5+4

R

p

=

19

20

Ω

(b) R

1

=2Ω,R

2

=4Ω,R

3

=5Ω

I

1

=

R

1

V

=20/2=10A

I

2

=

R

2

V

=20/4=5A

I

3

=

R

3

V

=20/5=4A

Total current = I

1

+I

2

+I

3

=19A