Question

A circuit consists of two parallel resistors having resistances of 20ohm and 30ohm respectively connected in series with a 15ohm resistor. If current through 15ohm resistor is 3A Evaluate(i) Current through the branches. (ii) Vottages accross whole cuicuit. (iii) Power consumed by 20ohm and 15ohm resistors .
ONLY RELEVANT ANSWERS!!​

Answer 1

Answer:

Answer:

Step-by-step explanation:

ANSWER:

There are two types of Circuits:-

\boxed{\textbf{PARALLEL CIRCUITS}}

PARALLEL CIRCUITS

In this type the resistances are added by adding their reciprocals and at last we again reciprocal the sum to get required answer.

\boxed{\textsf{SERIES CIRCUITS}}

SERIES CIRCUITS

In this type resistances are simply added to get the equivalent resistance.

Let the total Resistance be R.

Calculating Parallel circuit first,

GIVEN:-

2 Resistances of 20 ohm and 30 ohm.

Let the Equivalent resistance be R'.

\frac{1}{R'} = \frac{1}{20} +\frac{1}{30}

R

′

1

=

20

1

+

30

1

Taking LCM,

\frac{1}{R'} =\frac{3+2}{60} \implies \frac{5}{60} \implies \frac{1}{12}

R

′

1

=

60

3+2

⟹

60

5

⟹

12

1

\boxed{\boxed{\textsf{R' = 12 ohms}}}

R’ = 12 ohms

Now we will add R' with 15 Ohm as it is in Series:-

R = 12+15

\boxed{\boxed{\textbf{R = Total Resistance = 27 Ohms}}}

R = Total Resistance = 27 Ohms

Now we need to find the voltage.

\huge{\textsf{V = IR}}V = IR

Where V is voltage

Where I is current

Where R is Resistance

So,

V = 3 * 27

\boxed{\boxed{\textsf{Voltage = 81 Volts}}}

Voltage = 81 Volts

Now we need to find Current through each resistors where voltage will be same .

Using same Formula for 20 ohm first,

81 = 20*I

I = 81/20

\boxed{\textbf{Current through 20 Ohm resistor = 4.05 Ampere}}

Current through 20 Ohm resistor = 4.05 Ampere

Using the same formula for 30 ohm now,

81 = 30*I

I = 81/30

\boxed{\textsf{Current through 30 Ohm resistor = 2.7 Amperes}}

Current through 30 Ohm resistor = 2.7 Amperes

Explanation:

here is the answer