Question

a circuit contains four resistor connected in series . resistor R1 has a resistance of 45 ohms . resistor R2 has a resistance of 117 ohms. resistor R3 has a resistance of 71 ohms.and resistor has R4 has resistance of 169 ohms. if the battery has a voltage of 45.0 v . calculate the voltage across each resistor. V1,V2,v3

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Answer 1

Answer:

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Answer 2

Explanation:

• R1 = 45 ohms
• R2 = 117 ohms
• R3 = 71 ohms
• R4 = 169 ohms
• Battery voltage v = 45 v
• So we have the ohm’s law V = I x R
• Now we have the total resistance 45 + 117 + 71 + 169 = 402 ohms
• So current will be I = V/R
•                                  = 45/402 Amps
• Now it is in series, so voltage drop across each resistor will be
•  So  V = I R1
•        V = 45 / 402 x 45
•        V = 5.03 V
• So V = I R2
•        = 45/402 x 117
•         = 13.09 V
• So V = I R3
•         = 45/402 x 71
•          = 7.94 V
• So V = I R4
•         =  45/402 x 169
•          = 18.9 V

Reference link will be

https://brainly.in/question/17769715