a circuit contains four resistor connected in series . resistor R1 has a resistance of 45 ohms . resistor R2 has a resistance of 117 ohms. resistor R3 has a resistance of 71 ohms.and resistor has R4 has resistance of 169 ohms. if the battery has a voltage of 45.0 v . calculate the voltage across each resistor. V1,V2,v3
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Answer:
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Answer:
V1 = 5.0355
V2 = 13.09
V3 = 7.95
V4 = 18.91
Step-by-step explanation:
First we have to find the R_eq which is
Req = 402
Now current through circuit is
I = V /(Req) = 45/ 402=0.1119
Now
V1 = IR1 = (0.1119)(45)=5.0355
v2 = IR2= (0.1119)(117) = 13.09
V3 = IR3=((0.1119)(71)= 7.95
V4 = IR4 = ((0.1119) (169)=18.91
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