A circuit has a fuse of 5 A. What is the maximum number of 100 watt (220 V) bulbs which can be safely used in the circuit?
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P=VI
=> P = 220×5
=1100
As power is given 100watt.
So, bulbs required are 1100÷100 = 11.
Hope it helps you ^•^
Thank you and please mark it as brainliest answer
=> P = 220×5
=1100
As power is given 100watt.
So, bulbs required are 1100÷100 = 11.
Hope it helps you ^•^
Thank you and please mark it as brainliest answer
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