A circuit has a fuse of 5a.find the maximum number of 100w 220v bulbs that can be used in a circuit.
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Answer:
Explanation:
Given :-
Power, P = 100 W
Voltage, V = 220 V
Now current, I max = 5 A
To Find :-
Number of bulbs which can be used, n = ???
Formula to be used :-
From Relation, P = VI
We Have, I = P/V
Solution :-
Putting all the values, we get
⇒ I = 100/220
⇒ A = 5/11 A
For bulb, in parallel, I max = n I
We have, n = I max/ I
Putting values, we get
⇒ n = 5 × 11/5
⇒ n = 11
Hence, 11 bulbs can be used safely in the circuit.
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