Question

A circuit having three resistors (R1) 7.2ohm, (R2) 8ohm and (R3) 12ohm are connected in such a

way that

their resultant resistance is 12. How are they connected?​

Answer 1

Explanation:

Sorry I don't know the answer....

Answer 2

Explanation:

if resistance are connected in series then it's resultant resistance will be summation of all resistances.

if they are connected in parallel then reciprocal of resultant is sum of reciprocal of connected resistances.

1/R=1/7.2+1/8+1/12