A circuit is connected for use as a potential divider. The resistance of X is 10Ω. When the resistance of the variable resistor Y is 20Ω, what is the reading on the voltmeter?
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Answer: 8.0 V
Explanation: The original voltage (12) is the sum of both voltage 1 (the one that you're looking for) and voltage 2 (unknown). We know that voltage 2 is half of voltage 1 (because 10 is half of 20) so if you add 8V as V1 and 4V as V2, it will give you the final total voltage 12V
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