a circuit is made of 0.4 ohm wire, a 150 ohm bulb ,a 120 ohm rheostat connected in series. determine the total resistance of the resistance of the circuit
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R1 =0.4
R2=120
R3=150
In,series rs= R1+R2+R3
Calculation:- 0.4+150+120=270.4ohm
R2=120
R3=150
In,series rs= R1+R2+R3
Calculation:- 0.4+150+120=270.4ohm
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