A circuit is made of 0.4 ohm wire, a 150 ohm bulb and a 120 ohm rheostat connected in series. determine the total resistance of the circuit.
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when connected in series, R=r1+r2+r3=0.4+150+120ohm=27.4ohm.
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Answer:
R1 =0.4 Ω
R2=120 Ω
R3=150 Ω
In,series resistance= R1+R2+R3
Calculation:- 0.4+150+120=270.4ohm
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