Question

A circuit is made of 0.4 ohm wire, a 150 ohm bulb and a 120 ohm rheostat connected in series. determine the total resistance of the circuit.

Answer 1

when connected in series,                                                                                        R=r1+r2+r3=0.4+150+120ohm=27.4ohm.

Answer 2

Answer:

R1 =0.4 Ω

R2=120 Ω

R3=150 Ω

In,series resistance= R1+R2+R3

Calculation:- 0.4+150+120=270.4ohm

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