Question

a circuit is shown in the diagram given below , find the value of r and find the reading of ammeter​

Answer 1

Answer:

Hope it helps u

Explanation:

(a) Since R and 6 resistors are in series, same current flows through them, i.e.,

    Current 'I' through the resistor can be written as (6V / R)

    I = V / R

$\frac{6V}{R} =\frac{12 V}{R} => R = 3$ Ohm  

 (ii) Ammeter reading will be same as current through R, i.e.

$\frac{6V}{3ohm} = 2A$

 (iii) Potential difference across the battery terminals is  $6V + 12 V= 18 V$

The measurements are not given in question but.. i got the proper question

Thanks

MARK AS BRAINLIEST

Answer 2

Answer:

Hope it helps u

Explanation:

(a) Since R and 6 resistors are in series, same current flows through them, i.e.,

Current 'I' through the resistor can be written as (6V / R)

I = V / R

\frac{6V}{R} =\frac{12 V}{R} = > R = 3

R

6V

=

R

12V

=>R=3 Ohm

(ii) Ammeter reading will be same as current through R, i.e.

\frac{6V}{3ohm} = 2A

3ohm

6V

=2A

(iii) Potential difference across the battery terminals is 6V + 12 V= 18 V6V+12V=18V

The measurements are not given in question but.. i got the proper question

Thanks