Question

a circular arc of length 22cm subtends an angle theta at the centre of the circle of radius 21cm. the value of theta is

Answer 1

Answer:

The value of theta is 60°

Explanation:

The circular arc of length 22cm subtends an angle theta at the centre of the circle of radius 21cm.

From the question, we have

Circular arc of length = 22 cm

$22 = \frac{\theta *2 \pi r}{360}\\22 = \frac{\theta *2 \pi *21}{360} \\\theta = 60^{o}$

Multiplication:

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Answer 2

The value of θ  is 60°.

The circular arc of length 22cm subtends an angle theta at the centre of the circle of radius 21cm.

From the question, we have

Circular arc of length = 22 cm

Circular arc of length = 22 cm

22 = $\frac{theta *2\pi r}{360}$

22 x 360 = θ x 2π x 22

θ  = 22 x 360/ 44π

θ   = 60°.

Hence the value of θ is 60.

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