Question

A circular ball resting on a smooth triangular channel. One of the sides of channel is inclined at 60 degrees with
horizontal The inclination of the reaction will be
a 90 degrees
Zero degrees
c. 30 degrees
d 60 degrees

Answer 1

Answer:

A is the write answer please note that

Answer 2

Answer:

The inclination of reaction is $60$ degrees. Option d) is correct.

Explanation:

• When an object is placed on an inclined plane the reaction due to the plane is not vertical but at a particular angle.
• The weight acts always in a vertically downwards direction.

In an equilibrium state the formula is:

$N=W$

where $N =$ normal reaction due to plane.

            $W=$ weight of the body.

Step 1:

Here, the bell is resting on the channel making an angle $60$ degrees with horizontal.

The weight acts downwards for the circular ball.

Along the channel the horizontal component of weight is $Wsin60^{0}$.

Step 2:

The vertical component of weight is along the channel is $Wcos60^{0}$.

This is balanced by the reaction provided by the plane.

So, the inclination of reaction is $60$ degrees.

Option d) is correct.