Question

A circular car racetrack has inner circumference of 272 m and outer circumference of 304m. Find the width of the track.​

Answer 1

Step-by-step explanation:

Circumference of inner track=272

radius of inner track =circumference/2π

=272/2*22/7

427.42

circumference of outer track=304m

radius of outer track=304/2*22/7

=477.71m

Width of track=477.71-427.42

=50.294m

Answer 2

The width of the track is about 5.20 m

Explanation:

Circumference of a circle = $2\pi r$ , where r  = radius of the circle.

Given : A circular car racetrack has inner circumference of 272 m and outer circumference of 304m.

Let r= the radius of inner circle.

R = the radius of outer circle.

Then, $2\pi r =272$

$r=\dfrac{272}{2\pi}=\dfrac{136}{\pi}$

$2\pi R=304\\\Rightarrow\ R=\dfrac{152}{\pi}$

Width of track = R-r

$=\dfrac{152}{\pi}-\dfrac{136}{\pi}=\dfrac{16}{\pi}\\\\=\dfrac{16}{3.14}=5.0955414\approx5.20\ m$

Hence, the width of the track is about 5.20 m

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