Question

A circular coil 300 turns and diameter 14 cm carries a current of 15 A. What is the magnitude of magnetic

moment of associated with the coil?​

Answer 1

Answer:

69.3

Explanation:

magnetic moment = no of turns multiplied current and area

Answer 2

The magnetic  moment of associated with the coil is 69.27 J/T.

Explanation:

Given that,

Number of turns in the coil, N = 300

Diameter of the coil, d = 14 cm

Radius, r = 7 cm = 0.07 m

Current, I = 15 A

We need to find the magnetic  moment of associated with the coil. It is given by :

$M=NIA\\\\M=NI\pi r^2\\\\M=300\times 15\times \pi (0.07)^2\\\\M=69.27\ J/T$

So, the magnetic  moment of associated with the coil is 69.27 J/T.

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