A Circular coil of 100 turns with a cross sectional area (A) of 1m2 is kept with its plane perpendicular to the magnetic field (B) of 1T.What is the magnetic flux linkage with the coil ?
Answers
Answer: The magnetic flux in the coil is = 100 T/m².
Explanation:
[Refer to the attached image for direction conventions.]
The magnetic flux of a substance is the dot product of the magnetic field and the area of the substance.
Ф = B . A = BAcosθ
Where,
Φ = flux through one turn
B = Magnetic field in that region
A = area
θ = angle between the field line and the area vector
As per the given question,
θ = 0° (as the area vector and the magnetic field are in the same direction)
A = 1m²
B = 1T
Now,
Φ = 1 x 1 cos 0°
=> Ф = 1
Now, the flux through 100 coils will be 100 x 1 = 100 T/m²
Therefore, the magnetic flux in the coil is = 100 T/m².
Answer:
The required magnetic flux is 100 Weber.
Explanation:
- Magnetic flux is said to be the measure of the total magnetic field passing through a particular given area.
- It has Weber (Wb) as its S.I unit.
- Magnetic flux is expressed by the following formula;
where,
Ф = magnetic flux
N = number of turns
B = magnetic field
A = cross-sectional area
Here,
N = 100 turns
A = 1 m²
B = 1 T
cos∅ = cos 0° = 1 (∵ plane is ⊥ to the magnetic field)
∴ Ф = 100 × 1 × 1 × cos 0°
= 100 × 1 × 1 × 1
= 100 Weber
Therefore, a circular coil with 100 turns will have 100 Weber magnetic flux in a magnetic field of 1 Tesla.