Physics, asked by titikshapatil098, 9 months ago

A Circular coil of 100 turns with a cross sectional area (A) of 1m2 is kept with its plane perpendicular to the magnetic field (B) of 1T.What is the magnetic flux linkage with the coil ?​

Answers

Answered by siddharthapriy72
1

Answer: The magnetic flux in the coil is = 100 T/m².

Explanation:

[Refer to the attached image for direction conventions.]

The magnetic flux of a substance is the dot product of the magnetic field and the area of the substance.

Ф = B . A = BAcosθ

Where,

Φ = flux through one turn

B = Magnetic field in that region

A = area

θ = angle between the field line and the area vector

As per the given question,

θ = 0° (as the area vector and the magnetic field are in the same direction)

A = 1m²

B = 1T

Now,

    Φ = 1 x 1 cos 0°

=> Ф = 1

Now, the flux through 100 coils will be 100 x 1 = 100 T/m²

Therefore, the magnetic flux in the coil is = 100 T/m².

Attachments:
Answered by Pamelina15
1

Answer:

The required magnetic flux is 100 Weber.

Explanation:

  • Magnetic flux is said to be the measure of the total magnetic field passing through a particular given area.
  • It has Weber (Wb) as its S.I unit.
  • Magnetic flux is expressed by the following formula;

                                           \phi=NBA\cos \theta

where,

         Ф = magnetic flux

         N = number of turns

         B = magnetic field

         A = cross-sectional area

Here,

N = 100 turns

A = 1 m²

B = 1 T

cos∅ = cos 0° = 1 (∵ plane is ⊥ to the magnetic field)

                 ∴ Ф  = 100 × 1 × 1 × cos 0°

                         = 100 × 1 × 1 × 1

                         = 100 Weber

Therefore, a circular coil with 100 turns will have 100 Weber magnetic flux in a magnetic field of 1 Tesla.

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