Question

A circular coil of 100 turns with a cross-
sectional area (A) of 0.5 m² is kept with
its plane perpendicular to the magnetic
field (B) of 4T. What is the magnetic
flux linkage with the coil?
(A) 400 Wb
(B) 100 Wb
(C) 50 Wb (D) 200 Wb​

Answer 1

Answer:

The magnetic  flux linked with the coil is 200Wb.

Explanation:

We know that $\phi$ = n B A cos $\theta$

where $\phi$ = Magnetic flux associated with the coil

           n = Number of turns of the coil

           B = Magnetic field

           A = Cross sectional area of the coil

           $\theta$ = Angle between magnetic field and the normal to the plane of coil

Here, given that

n = 100

B = 4T

A = 0.5m²

$\theta$  = 0° as the magnetic field and normal to the plane of the coil are in the same direction.

Therefore, on substituting the values in the formula, we get,

   $\phi$ = n B A cos $\theta$

      = 100*4*0.5*cos0

      = 100*4*0.5*1

      = 200Wb

Therefore, the magnetic  flux linked with the coil is 200Wb.