A circular coil of 200 turns and of radius 20 cm carries a current of 5A .Calculate the magnetic induction at a point along its axis ,at a distance three times the radius of the coil from its center.
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Answer:
Given:
n=200
a=20 cm=.2 m
I=5 A
x=3a
B=
2(a
2
+x
2
)
3/2
nμ
0
Ia
2
Substitution and simplification
B=9.9×10
−5
T
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