Question

A circular coil of 20turns and radius 10cm carries a current of 5A. It is placed in a uniform magnetic field of 0*10T. Find the torque acting on the coil when the magnetic field is applied (a) normal to the plane of the coil (b) in the plane of coil. Also find out the total force acting on the coil.

Answer 1

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$\huge\boxed{\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}}$

(a)The total torque on coil is zero because the field is uniform.

(b)The total force on coil is zero as field is uniform.

(c)Force, F=B

e

×V

d

V

d

=drift velocity=

NeA

I

$$F=5\times 10^{-25}N$$ on each electron.

Answer 2

Answer:

the total force is 5×10^25 J

the relation connecting voltage, number of turns and current flowing is given by

Vs/Vp=Ns/Np=Ip/Is

here p represent primary and. s represent secondary