Question

A circular coil of 8 turns and mean radius 10 cm carries a current of 1A and the magnitude of magnetic induction at its centre

Answer 1

magnetic induction is given by, $B=\frac{\mu_0Ni}{2R}$

where $\mu_0$ is permeability of medium, N is number of turns , i is current through circular loop and R is the the radius of the loop.

here, $\mu_0$= 4π × 10^-7 Tm/A

N = 8 , R = 10cm = 0.1m and i = 1A

so, B = 4π × 10^-7 × 8 × 1/2(0.1)

= 32π × 10^-7/0.2

= 160π × 10^-7 T

= 502.4 × 10^-7 T

= 5.024 × 10^-5 T

hence , magnetic induction is 5.024 × 10^-5 T