A circular coil of area 100 sq cm with its plane inclined at an angle of 60° with the direction of a uniform field of strength 0.2 Tesla.
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Answer :
Area of plane = 100 cm²
Angle of inclination = 160°
Strength of magnetic field = 0.2 T
We have to find magnetic flux associated with circular coil.
Diagram :
Refer to the attachment!
Magnetic flux associated with a plane placed in a uniform magnetic field at an angle θ is given by
- ϕ = B • A = BA cosθ
ϕ denotes magnetic flux
B denotes magnetic field
A denotes area
θ denotes angle b/w B and A
★ Conversion :
- 1 cm² = 0.0001 m²
∴ 100 cm² = 100/10000 = 0.01 m²
★ Calculation :
➙ ϕ = BA cosθ
➙ ϕ = 0.2 × 0.01 × cos60°
➙ ϕ = 0.002 × 1/2
➙ ϕ = 0.001 Tm²
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