A circular coil of conducting
wire has 500 turns and an area 1.26×10-4 m2
is enclosed by the coil. A current 100 µA
is passed through the coil. Calculate the
magnetic moment of the coil.
Answers
Answered by
42
Solution:
µ = NIA
= 500 × 100 × 10-6 × 1.26 × 10-4 Am2
= 630 × 10-8 = 6.3 × 10-6 Am2or J/T.
Answered by
9
Answer:
Initial magnetic flux through the coil,
ϕ
1
=B
H
Acosθ=3.0×10
−5
×(π×10
−2
)×cos0
∘
=3π×10
−7
Wb
Final magnetic flux after the rotation
ϕ
f
=3.0×10
−5
×(π×10
−2
)×cos180
∘
=−3π×10
−7
Wb.
Induced emf, ϵ=−N
dt
dϕ
=−
t
N(ϕ
f
−ϕ
i
)
=−
0.25
500(−3π×10
−7
−3π×10
−7
)
=
0.25
500×(6π×10
−7
)
=3.8×10
−3
V
I=
R
ϵ
=
2Ω
3.8×10
−3
V
=1.9×10
−3
A.
mark it as brainyest ................
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