Question

A circular coil of one turn in formed by 6.28 m length wire which carried a current of 3.14 A magnetic field at the center of coil

Answer 1

Answer:

Explanation:

Given A circular coil of one turn in formed by 6.28 m length wire which carried a current of 3.14 A magnetic field at the center of coil

Given length = l = 6.28 m , I = 3.14 A

= 2 x 3.14  

= 2π m

Again for coil we have l = 2πr

                               2π = 2πr

                     So r = 1 m

We know that

Magnetic field of coil = μo I / 2r

                                   = 4π x 10^-7 x 3.14 / 2 x 1

                                  = 19.7 x 10 ^-7

                                  = 1.97 x 10^-6

                                  = 1.97 μ T

Answer 2

Explanation:

When it convert to coil

l=2πr

2π=2π×r

r=Lm

Magnetic field of coil =

2r

μ

0

I

=

2×L

4π×10

−7

×3.14

=19.7×10

−7

=1.97×10

−6

B≈2μT