Question

A circular coil of radius 10 cm and 20 turn is rotated about its verical diameter witn angular speed of 50 rad/s in a uniform horizontal magnetic field of 3* 10^-2 (1) calculate the maximum and average emf induced in the coil (2) if the coil forms a closed loop of resistance 10 ohm claculate the maximum current in the coil and the acerage power loss due to joule heating????

Answer 1

Answer: The maximum induced emf is $E_{0}= 0.942\ V$, the average induced emf is zero, the maximum current is 0.0942 A and the power is 0.044 W.

Explanation:

Given that,

Radius r = 10 cm

Number of turns N = 20

Resistance R = 10 ohm

Angular speed $\omega = 50\ rad/s$

Magnetic field $B=3\times10^{-2}\ T$

We know that,

(i). The average emf induced in the coil is

$E_{0}= NBA\omega$

$E_{0}= 20\times3\times10^{-2}\times 3.14\times10\times10\times10^{-4}\times 50$

$E_{0}= 0.942\ V$

The maximum induced emf is 0.942 V.

The average emf induced in the coil is zero for a full cycle.

(ii). The maximum current in the coil is

$I = \dfrac{E_{max}}{R}$

$I = \dfrac{0.942}{10}$

$I = 0.0942\ A$

The power loss due to joule heating is

$P = \dfrac{EI}{2}$

$P = \dfrac{0.942\times0.0942}{2}$

$P= 0.044\ W$

Hence, The maximum induced emf is $E_{0}= 0.942\ V$, the average induced emf is zero, the maximum current is 0.0942 A and the power is 0.044 W.

Answer 2

Explanation:

I hope it Will help you..