A circular coil of radius 3 cm has 50 turns. It is placed on the horizontal plane and a current of 3 A flows through it in clockwise direction as seen from the above. Calculate the magnetic field at a point on the axis of the coil, at a distance of 4 cm from its centre. Also indicate the direction of the magnetic field.
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Answer:
Explanation:
Radius of circular coil R=20 cm=0.2 m
Current flowing I=5 A
Number of turns N=100
Magnetic field at a distance x on the axis, B=
2(R
2
+x
2
)
3/2
μ
o
INR
2
where x=20 cm=0.2 m
B=
2(0.2
2
+0.2
2
)
3/2
4π×10
−7
×5×100×(0.2)
2
=5.6×10
−4
T
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