A circular coil of radius 30cm and resistance π2Ohms is rotating in a uniform magnetic field B=10−2. Axis of rotation is diameter of coil which is perpendicular to direction of B. If Coil rotates with 200rpm the current induced in coil is
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Given, n = 1, B = 10-2 T,
A = p(0.3)2 m2, R = p2
f = (200/60) and w = 2pi(200/60)
Substituting these values and solving, we get
I = 6 × 10-3 A = 6m A
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