Question

A circular coil of radius 5 cm and 50 turns carries a current of 3 ampere. The magnetic dipole moment of the coil

Answer 1

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Answer 2

The magnetic dipole moment of the coil is $1.18\ Amp\ m^2\ .$

Given :

Radius of coil , r = 5 cm = 0.05 m .

Number of turns , N = 50 .

Current flowing , I = 3 A .

We know , magnetic dipole moment of the coil is given by :

$B =NIA\\\\B=NI(\pi r^2)\\\\B=50\times 3\times \pi\times 0.05^2 \\\\B=1.18\ Amp\ m^2\ .$

Hence , this is the required solution .

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Magnetism

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