Question

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s−1 in a uniform horizontal magnetic field of magnitude 3.0×10 T. Obtain the maximum and average emf induced in the coil. If the coil for loop of resistance 10Ω, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating. Where does this power come from?​

Answer 1

Answer:

Maximum induced emf e=NωAB;

N=no. of turns,ω=angular speed,A=Area of coil,B=Magnetic field

⇒e=0.603V

Over a full cycle, the average emf induced in the coil is zero.

Maximum current, I=e/R=0.0603

Average power loss due to joule heating is P=  

2

eI

​

=0.018 W

Step-by-step explanation:

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