Question

A circular coil of radius 8 cm and 20 turns rotates about its vertical diameter with
an angular speed of 50 s --1in a uniform horizontal magnetic field of magnitude3×102 T. Find the maximum and average value of the emf induced in the coil.

Answer 1

it's vertical diameter is 50 s--1a uniform horizontal magnet field of magnitude

Answer 2

Explanation:

Given,

Radius of the circular coil,r = 8.0 cm = 0.08 m

No. of turns in the coil, N =20

Angular frequency ω = 50 rad/s

Magnitude of magnetic field B =3.0 × 10^-2 T

Resistance of the closed loop = 10 Ω

The area of the coil can be calculated using the formula

A =πr² = 3.14 × (0.08 m)²

The maximum induced e.m.f is calculated as follows:e = NωAB

e = 20 × 50 rad/s × 3.14 × (0.08 m)² × 3.0 × 10^–2 T

e = 0.603 V

For a complete cycle, the average induced emf will be zero.

The maximum current for the circular coil can be calculated as follows:

I = e/R

Substituting the values

I = 0.603 V/10 Ω

I = 0.0603A

The average power loss due to Joule’s heating effect in the circular coil will be given by:

P = (ei)/2

P = (0.603 V × 0.0603 A)/2

1. P = 0.018 W. m