Question

A circular coil of radius R having N number of turns carries a steady current I. the magnetic induction at the Centre of the coil is 0.1 tesla. if the number of turns is doubled and the radius is halved, the magnetic induction at the Centre of the coil will be​

Answer 1

Answer:

formula B = (N x uo x I )/ 2 x r

Explanation:

0.1 = (N x uo x I)/ 2 x R

if N¹ = 2N

R¹ = R/2

then B = (N¹ x uo x I)/ 2 x R¹

= ( 2N x uo xI)/2 x R/2

= 2 ( N x uo xI) /R

= 4 ( N x uo x I)/2 x R

= 4 x 0.1 = 0.4T