Physics, asked by ramamoorthie5270, 3 months ago

A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field B. The work done to rotate the loop by 90 degrees about an axis perpendicular to its plane is *

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Answered by Anonymous
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Let the magnetic moment M->M of current

Let the magnetic moment M->M of currentloop make an angle aa with the direction

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop is

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° about

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is no

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is nochange in the angle in the angle aa

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is nochange in the angle in the angle aaHence 61-ae1=a and 02=a02=a work done

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is nochange in the angle in the angle aaHence 61-ae1=a and 02=a02=a work doneW-MB(cose1-cose2)W=MB(cose1-cose2)

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is nochange in the angle in the angle aaHence 61-ae1=a and 02=a02=a work doneW-MB(cose1-cose2)W=MB(cose1-cose2)=MB(cosa-cosa)=MB(cosa-cosa)

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is nochange in the angle in the angle aaHence 61-ae1=a and 02=a02=a work doneW-MB(cose1-cose2)W=MB(cose1-cose2)=MB(cosa-cosa)=MB(cosa-cosa)=0=0

Let the magnetic moment M->M of currentloop make an angle aa with the directionof B-B When a current circular loop isrotated in a magnetic field by 30 30° aboutair axis perpendicular to its plane, there is nochange in the angle in the angle aaHence 61-ae1=a and 02=a02=a work doneW-MB(cose1-cose2)W=MB(cose1-cose2)=MB(cosa-cosa)=MB(cosa-cosa)=0=0Answer :zero.

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