Question

A circular cycle track has a circumference of 314 m
with AB as one of its diameter. A cyclist travels from Ato B along the circular path with a velocity of constant magnitude 15.7 m/s. Find the:
(a) distance moved by the cyclist.
(b) displacement of the cyclist, if AB represents north-south direction.
(c) the average velocity of the cyclist.​

Answer 1

a) Distance=314m

b)Displacement=100m

$diameter = displacement = \\ d = \frac{314}{3.14} = 100m$

Answer 2

A)Distance =314

B)Displacement =100

C)D=314/3.14=100