Question

A circular cycle track has a circumference of 314m with AB as one of its diameters. A cyclist travels from A to B along the circular path with a velocity of constant magnitude 15.7 m/s. Find:
(a) the distance moved by the cyclist.
(b) the displacement of the cyclist if AB represents north- south direction.
(c) the average velocity of the
cyclist.

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Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Given;

circumference 2 $\pi r$ = 314 m

radius = $\frac{314}{2\pi }$

    = 314/ 2 x 3.14

     = 50 m

a, distance move, = 1/2 x circumference

  = $\frac{1}{2}$ x 314 = 157 m

b, Displacement of AB = 2r = 100 m

   Displacement in north - south direction.

c, Time taken  going from A to B =  $\frac{157 m}{15.7 m/s}$ = 10 s

      average velocity = $\frac{Displacement }{Time}$

                                  =   $\frac{100}{10}$

                               =  10 m , in north- south direction